Asked by Ebube
The second and fifth terms of a geometric progression (GP) are 1 and 1 respectively.find (a) common ratio
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8
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8
Answers
Answered by
Reiny
Use your definitions
2nd term : ar = 1
5th term : ar^4 = 1
divide:
r^3 = 1
r = 1
the ar = 1
a(1) = 1
a = 1
your GP is 1,1,1,....
(not a very exciting sequence, some authors would exclude r = 1 in a GP)
2nd term : ar = 1
5th term : ar^4 = 1
divide:
r^3 = 1
r = 1
the ar = 1
a(1) = 1
a = 1
your GP is 1,1,1,....
(not a very exciting sequence, some authors would exclude r = 1 in a GP)
Answered by
Steve
I think that the attempt at including a fraction has bungled the posting. I read it as
The second and fifth terms of a geometric progression (GP) are 1 and 1/8 respectively. Find (a) common ratio
T5/T2 = r^3 = 1/8
so,
r = 1/2
The second and fifth terms of a geometric progression (GP) are 1 and 1/8 respectively. Find (a) common ratio
T5/T2 = r^3 = 1/8
so,
r = 1/2
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