Question
What is the normal concentration of an HNO3 solution if 412 mL of the solution is titrated by 147 mL of 2.03-N NaOH?
What is the normal concentration of a Ba(OH)2 solution, given that 86.3 mL of the solution is titrated by 113.0 mL of 0.00715-N H3PO4?
What is the normal concentration of a Ba(OH)2 solution, given that 86.3 mL of the solution is titrated by 113.0 mL of 0.00715-N H3PO4?
Answers
1.
mL x N = mL x N
412 x N HNO3 = 147 x 2.03
Solve for N HNO3
2. Follow #1 problem.
mL x N = mL x N
412 x N HNO3 = 147 x 2.03
Solve for N HNO3
2. Follow #1 problem.
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