What is the normal concentration of an HNO3 solution if 412 mL of the solution is titrated by 147 mL of 2.03-N NaOH?

Question

What is the normal concentration of a Ba(OH)2 solution, given that 86.3 mL of the solution is titrated by 113.0 mL of 0.00715-N H3PO4?

Answer 1

1.
mL x N = mL x N
412 x N HNO3 = 147 x 2.03
Solve for N HNO3

2. Follow #1 problem.