Question
What are the molar concentrations of H3O+ and OH- in 0.200 M NaOCL
Answers
DrBob222
...........OCl^- + HOH ==> HOCl + OH^-
initial....0.200M.............0........0
change.....-x...............x.........x
equil....0.200-x............x..........x
Kb = (Kw/Ka) = (x)(x)/((OCl^-)
You know Kw, Ka and OCl, substitute and solve for x, convert to pOH, then to OH^- and H^+
initial....0.200M.............0........0
change.....-x...............x.........x
equil....0.200-x............x..........x
Kb = (Kw/Ka) = (x)(x)/((OCl^-)
You know Kw, Ka and OCl, substitute and solve for x, convert to pOH, then to OH^- and H^+