Asked by Caity
how to solve for 3loga(2x+1)-2loga(2x-1)
Answers
Answered by
Reiny
nothing to solve, you don't have an equation.
If you are simplifying ....
3loga(2x+1)-2loga(2x-1)
= loga(2x+1)^3 - loga(2x-1)^2
= loga [ (2x+1)^3 / (2x-1)^2 ]
not really simplifying, just changing it around a bit
If you are simplifying ....
3loga(2x+1)-2loga(2x-1)
= loga(2x+1)^3 - loga(2x-1)^2
= loga [ (2x+1)^3 / (2x-1)^2 ]
not really simplifying, just changing it around a bit
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