Asked by KG
A ship is heading due north at 10 mph. The current is flowing southwest at 3 mph. Find the actual bearing and speed of the ship.
Answers
Answered by
kanchan
The ship is heading towards north with a speed of 10mph. The current is flowing towards southwest. By parallelogram law of vectors the resultant will be in direction north west.You can calculate the speed by the formula (V^2+v^2+2Vv cos 120) where V=speed of ship , v=speed of current. Reply if I am correct or not.
Answered by
Arora
Just a tiny correction, the formula (V^2+v^2+2Vvcos120) will give you the square of the resultant speed, not the speed itself.
Answered by
kanchan
Thank you very much Arora for your correction.
Answered by
Reiny
If that is the cosine law formula, it should be
d^2 = V^2+v^2 - 2Vvcos120
d^2 = V^2+v^2 - 2Vvcos120
Answered by
Bug
Where do you get 120 degrees
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