Question
1. How does the strenght of a covalent bond relate to bond length?
2. Compare the degree of polarity in HF, HCL, HBr, and HI?
3. Given that it has the highest electronegativity, can a fluorine atom ever from a non-polar covalent bond?
Explain your answer.
2. Compare the degree of polarity in HF, HCL, HBr, and HI?
3. Given that it has the highest electronegativity, can a fluorine atom ever from a non-polar covalent bond?
Explain your answer.
Answers
Chopsticks
I think that the longer the bond length the weaker the covalent bond.
DrBob222
1. How does the strenght of a covalent bond relate to bond length?
<b>Weaker bonds have longer bond lengths; stronger bonds have shorter bond lengths.</b>
2. Compare the degree of polarity in HF, HCL, HBr, and HI?
<b>Look up the electronegativity of each element in the pair and subtract them. The more difference the more ionic the bond (more polar). For example,
H is 2.1 and F is 4.0. Difference is 1.9
H is 2.1 and Cl is 3.5. Difference is 1.4. Therefore, HF has more ionic character (more polar) than HCl.</b>
3. Given that it has the highest electronegativity, can a fluorine atom ever from a non-polar covalent bond?
Explain your answer.
<b>Of course. What about F2 (F bonding with itself)? So the difference in EN is 4.0 - 4.0 = 0 and it is a covalent bond (100% covalent). </b>
<b>Weaker bonds have longer bond lengths; stronger bonds have shorter bond lengths.</b>
2. Compare the degree of polarity in HF, HCL, HBr, and HI?
<b>Look up the electronegativity of each element in the pair and subtract them. The more difference the more ionic the bond (more polar). For example,
H is 2.1 and F is 4.0. Difference is 1.9
H is 2.1 and Cl is 3.5. Difference is 1.4. Therefore, HF has more ionic character (more polar) than HCl.</b>
3. Given that it has the highest electronegativity, can a fluorine atom ever from a non-polar covalent bond?
Explain your answer.
<b>Of course. What about F2 (F bonding with itself)? So the difference in EN is 4.0 - 4.0 = 0 and it is a covalent bond (100% covalent). </b>