Asked by Anonymous
Consider the following system, which is at equilibrium,
CO(g) + 3 H2(g) <--------> CH4(g) + H2O(g).
The result of removing some CH4(g) and H2O(g) from the system will be
A. more CH4 is consumed to restore the equilibrium
B. Kc decreases
C. more H2O(g) is consumed to restore the equilibrium
D. more CO(g) is produced
E. more CH4(g) and H2O(g) are produced to replace that which is removed
The answer is E
I understand why the answer is E but why isn't the answer also be b?
CO(g) + 3 H2(g) <--------> CH4(g) + H2O(g).
The result of removing some CH4(g) and H2O(g) from the system will be
A. more CH4 is consumed to restore the equilibrium
B. Kc decreases
C. more H2O(g) is consumed to restore the equilibrium
D. more CO(g) is produced
E. more CH4(g) and H2O(g) are produced to replace that which is removed
The answer is E
I understand why the answer is E but why isn't the answer also be b?
Answers
Answered by
DrBob222
Tbe ONLY time the value of Kc changes is with temperature.
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