To find the linear equation represented by the second table, we can use the two points given in the table. Let's consider the points from the second table:
For the second table, the points are:
- \((-4, -5)\)
- \((-3, -7.5)\)
Step 1: Calculate the slope (m)
Using the formula for the slope \( m = \frac{y_2 - y_1}{x_2 - x_1} \):
Let’s choose the points \( (-4, -5) \) and \( (-3, -7.5) \):
- \( x_1 = -4, y_1 = -5 \)
- \( x_2 = -3, y_2 = -7.5 \)
Now, calculate the slope:
\[
m = \frac{-7.5 - (-5)}{-3 - (-4)} = \frac{-7.5 + 5}{-3 + 4} = \frac{-2.5}{1} = -2.5
\]
Step 2: Use the slope and one point to write the equation
We will use the point-slope form of the equation \( y - y_1 = m(x - x_1) \) with one of the points. Using point \((-4, -5)\):
\[
y - (-5) = -2.5(x - (-4))
\]
This simplifies to:
\[
y + 5 = -2.5(x + 4)
\]
Distributing the slope:
\[
y + 5 = -2.5x - 10
\]
Now, subtract 5 from both sides:
\[
y = -2.5x - 15
\]
The linear equation represented by the second table is:
\[
y = -2.5x - 15
\]
Step 3: Find the solution to the system of equations
Now we need to find the solution to the system of equations:
- \( y = 5.75x + 34.5 \)
- \( y = -2.5x - 15 \)
We can set these two equations equal to each other because both are equal to \( y \):
\[
5.75x + 34.5 = -2.5x - 15
\]
Now, let's solve for \( x \):
-
Add \( 2.5x \) to both sides:
\[
5.75x + 2.5x + 34.5 = -15
\]
\[
8.25x + 34.5 = -15
\]
-
Subtract 34.5 from both sides:
\[
8.25x = -15 - 34.5
\]
\[
8.25x = -49.5
\]
-
Divide by 8.25:
\[
x = \frac{-49.5}{8.25} = -6
\]
Step 4: Substitute \( x = -6 \) to find \( y \)
Now we can substitute \( x = -6 \) back into either equation to find \( y \). Let's use the first equation:
\[
y = 5.75(-6) + 34.5
\]
\[
y = -34.5 + 34.5
\]
\[
y = 0
\]
Final Answers:
The linear equation represented by the second table is:
\[
y = -2.5x - 15
\]
The solution to the system of equations is:
\[
(-6, 0)
\]