Solve using chain rule
y=(3x^3+1)(-4x^2-3)^4
So far, I have:
y'=(3x^3+1)*4(-4x^2-3)^3*(-8x)+(-4x^2-3)^4*(9x^2)
1 answer
fine so far
y=(3x^3+1)(-4x^2-3)^4
So far, I have:
y'=(3x^3+1)*4(-4x^2-3)^3*(-8x)+(-4x^2-3)^4*(9x^2)
1 answer