Asked by Mike
Solve using chain rule
y=(3x^3+1)(-4x^2-3)^4
So far, I have:
y'=(3x^3+1)*4(-4x^2-3)^3*(-8x)+(-4x^2-3)^4*(9x^2)
y=(3x^3+1)(-4x^2-3)^4
So far, I have:
y'=(3x^3+1)*4(-4x^2-3)^3*(-8x)+(-4x^2-3)^4*(9x^2)
Answers
Answered by
Damon
fine so far
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