Asked by Trace
A car traveling 35.0 m/s overtakes another car going only 22.0 m/s. When the faster car is still behind the slower one, it sounds a horn of frequency 1500.0Hz. What is the frequency heard by the driver of the slower car?
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Answers
Answered by
Henry
Fo = ((Vs+Vo)/(Vs-Vh)*Fh.
Fo = ((343+22)/(343-35))*1500 - 1777.6 Hz.
Fo = Freq. heard by the observer(slower driver).
Vs = Speed of sound.
Vo = Speed of the observer(slower driver).
Vh = Speed of the horn(faster driver).
Fh = Freq. of the horn.
Fo = ((343+22)/(343-35))*1500 - 1777.6 Hz.
Fo = Freq. heard by the observer(slower driver).
Vs = Speed of sound.
Vo = Speed of the observer(slower driver).
Vh = Speed of the horn(faster driver).
Fh = Freq. of the horn.
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