Asked by Mike
Calculate the Riemann sum of the area under the curve of f(x)=9-x^2 between x=-2 and x=3
The answer I come up with is 10/3, but when I solve using integrals, the answer I get is 100/3. Am I doing something wrong?
The answer I come up with is 10/3, but when I solve using integrals, the answer I get is 100/3. Am I doing something wrong?
Answers
Answered by
Reiny
looks like a decimal place error, check that.
Here is what Worlfram says:
http://www.wolframalpha.com/input/?i=riemann+sum+9-x%5E2+between+x%3D-2+and+x%3D3
Here is what Worlfram says:
http://www.wolframalpha.com/input/?i=riemann+sum+9-x%5E2+between+x%3D-2+and+x%3D3