Asked by Unsure
The temperature of a sample of neon is raised from 20 degrees C to 40 degrees C, the average kinetic energy of the neon atoms changes by a factor of?
The answer is suppose to be 313/293, but I don't get how.
My idea was since average KE = (3/2) kT then the KE would only change by 2. Can you help explain this to me?
The answer is suppose to be 313/293, but I don't get how.
My idea was since average KE = (3/2) kT then the KE would only change by 2. Can you help explain this to me?
Answers
Answered by
drwls
The average kinetic energy of atoms or molecules is proportional to the absolute temperature, T. You understand that already. (Note that is independent of atom or molecule weight!)
KE2/KE1 = (3/2)kT2/[(3/2)kT1] = T2/T1
The absolute temperature increases by a factor (273+40)/(273+20)= 313/293
So that is the answer.
KE2/KE1 = (3/2)kT2/[(3/2)kT1] = T2/T1
The absolute temperature increases by a factor (273+40)/(273+20)= 313/293
So that is the answer.
Answered by
Tushar
Temperature should be in Kelvin
Answered by
Abhishek
1/3
Answered by
Muskan
He is right
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