Asked by Liz
k. (64 to the root of 3)^4
l. (3 to the root of 4)^-8
f. (5^2/5/^2)^-1/2
4. The radius of a sphere r is given in terms of its volume V by the formula: r=(0.75V/π)^1/3 By how many inches has the radius of a spherical balloon increased when tthe amount of air in the ballon is increased from 4.2ft^3 to 24.9ft^3?
2. The gas used by a car on a rad trio can be found using the function g(d) =4d-7, where d is the distance traveled. The distance traveled by the same car at a given time, t, can be forgiven he using the function d(t)=2t+4. What is the amount of gas used by a car on a road trip as a function of time?
l. (3 to the root of 4)^-8
f. (5^2/5/^2)^-1/2
4. The radius of a sphere r is given in terms of its volume V by the formula: r=(0.75V/π)^1/3 By how many inches has the radius of a spherical balloon increased when tthe amount of air in the ballon is increased from 4.2ft^3 to 24.9ft^3?
2. The gas used by a car on a rad trio can be found using the function g(d) =4d-7, where d is the distance traveled. The distance traveled by the same car at a given time, t, can be forgiven he using the function d(t)=2t+4. What is the amount of gas used by a car on a road trip as a function of time?
Answers
Answered by
Liz
For k. I meant to put the cubed root of 64 in the parenthesis and for l. I meant to put the fourth root of 3.
Answered by
Steve
(64 to the root of 3)^4
= 4^4
= 256
(3 to the root of 4)^-8
= (3^1/4)^(-8)
= 3^-2
= 1/9
(5^2/5/^2)^-1/2
= 1^-1/2
= 1
or something. bad syntax
#4. Just plug in your two values of r and find the difference.
#2 Just substitute for d
g = 4d-7 = 4(2t+4)-7
= 4^4
= 256
(3 to the root of 4)^-8
= (3^1/4)^(-8)
= 3^-2
= 1/9
(5^2/5/^2)^-1/2
= 1^-1/2
= 1
or something. bad syntax
#4. Just plug in your two values of r and find the difference.
#2 Just substitute for d
g = 4d-7 = 4(2t+4)-7
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