Question
Solve each equation by using square roots, show all work.
2x^2-5=27
2x^2-5=27
Answers
cool
hi again
so first, you need to add 5 to both sides of the equation, so it becomes
2x^2 = 32
next, you divide BOTh sides by 2 because you are going reverse order of operations. this gets rid of the 2 in front of the x^2. so the equation becomes
x^2 = 32/2 which is
x^2 = 16
next, you find the square root of both sides. i dont have a symbol on my keyboard for square root but lets pretend
ok so the square root of x^2 is x. then you must find the square root of 16 (the other side of the equation), but when you take square root, it become PLUS or MINUS . so it would be PLUS or MINUS the square root of 16.
the positive square root of 16 is 4,and the negative of the square root of 16 is -4.
your answers are x = 4 and x = -4 :D
message back on this post if u have more questions
so first, you need to add 5 to both sides of the equation, so it becomes
2x^2 = 32
next, you divide BOTh sides by 2 because you are going reverse order of operations. this gets rid of the 2 in front of the x^2. so the equation becomes
x^2 = 32/2 which is
x^2 = 16
next, you find the square root of both sides. i dont have a symbol on my keyboard for square root but lets pretend
ok so the square root of x^2 is x. then you must find the square root of 16 (the other side of the equation), but when you take square root, it become PLUS or MINUS . so it would be PLUS or MINUS the square root of 16.
the positive square root of 16 is 4,and the negative of the square root of 16 is -4.
your answers are x = 4 and x = -4 :D
message back on this post if u have more questions