roots:
x=(3*sqrt2+-sqrt(18-16))/4
so those are the values.
Determine if the given value is a solution for each quadratic. Answer yes or no.
2x^2-3x(root 2)+2=0
I know the answer is yes but I don't know how to get to that answer.
Thanks a ton! :)
Kayla
3 answers
Just to simplify a bit,
(3√2±√2)/4 = √2 or √2/2
(3√2±√2)/4 = √2 or √2/2
So to find that I would need to go into decimals & leave exact form & then square my final answer to know that my answer was the root of 2?