Asked by SAM
For the following system of equations, what is the x value of the solution? -x + 2y =6 6y = x + 18
Answers
Answered by
Bosnian
- x + 2 y = 6
Subtract 2 y to both sides
- x + 2 y - 2 y = 6 - 2 y
- x = 6 - 2 y
6 y = x + 18
Subtract x to both sides
6 y - x = x + 18 - x
6 y - x = 18
Subtract 6 y to both sides
6 y - x - 6 y = 18 - 6 y
- x = 18 - 6y
- x = - x
6 - 2 y = 18 - 6 y
Add 2 y to both sides
6 - 2 y + 2 y = 18 - 6 y + 2 y
6 = 18 - 4 y
Subtract 18 to both sides
6 - 18 = 18 - 4 y - 18
- 12 = - 4 y
Divide both sides by - 4
- 12 / - 4 = - 4 y / - 4
3 = y
y = 3
- x + 2 y = 6
- x + 2 ∙ 3 = 6
- x + 6 = 6
Subtract 6 to both sides
- x + 6 - 6 = 6 - 6
- x = 0
Multiply both sides by - 1
x = 0
Subtract 2 y to both sides
- x + 2 y - 2 y = 6 - 2 y
- x = 6 - 2 y
6 y = x + 18
Subtract x to both sides
6 y - x = x + 18 - x
6 y - x = 18
Subtract 6 y to both sides
6 y - x - 6 y = 18 - 6 y
- x = 18 - 6y
- x = - x
6 - 2 y = 18 - 6 y
Add 2 y to both sides
6 - 2 y + 2 y = 18 - 6 y + 2 y
6 = 18 - 4 y
Subtract 18 to both sides
6 - 18 = 18 - 4 y - 18
- 12 = - 4 y
Divide both sides by - 4
- 12 / - 4 = - 4 y / - 4
3 = y
y = 3
- x + 2 y = 6
- x + 2 ∙ 3 = 6
- x + 6 = 6
Subtract 6 to both sides
- x + 6 - 6 = 6 - 6
- x = 0
Multiply both sides by - 1
x = 0
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