for simplicity, let u=sqrt(x^2+1)
-u/x+ ln(x+u)
the derivative is
u/x^2 -1/u du/dx + 1/(x+u) * (1+du/dx)
then, du/dx=1/2 (x^2+1)^-.5 (2x) or
x/sqrt(x^2+1) check me.
I get everything, but I can't seem to crack this one out, only one I got problems on..
-sqrt[x^2 +1]/x + ln(x + sqrt[x^2 + 1])
2 answers
I slugged it out the long way without bobpursley's substitution, and got a final of
√(x^2 + 1) / x^2
It would be a horrible mess to type, do you have an answer from the back of the book?
√(x^2 + 1) / x^2
It would be a horrible mess to type, do you have an answer from the back of the book?
1 answer