Asked by abinaya
a particle a of mass makes perfectly elastic collision with b which is at rest and fly apart in opp directions with same velocity then relation between their masses is
Answers
Answered by
Henry
Ma*Va + Mb*Vb = Ma*V - Mb*V.
Ma*Va + Mb*0 = V(Ma-Mb),
Divide both sides by V:
Ma*Va/V = Ma-Mb,
Divide both sides by Ma:
Va/V = 1-Mb/Ma,
Mb/Ma = 1 - Va/V.
Ma*Va + Mb*0 = V(Ma-Mb),
Divide both sides by V:
Ma*Va/V = Ma-Mb,
Divide both sides by Ma:
Va/V = 1-Mb/Ma,
Mb/Ma = 1 - Va/V.
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