Asked by jeet
1^3+3^3+5^3+.....to n terms.
Answers
Answered by
Steve
a useful sum to know is
n
∑(2k-1)^3 = n^2(2n^2-1)
k=1
n
∑(2k-1)^3 = n^2(2n^2-1)
k=1
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