A. t = 6.50h * 3600s/h = 23,400 s.
Po = W/t = 5.50*10^6J/2.34*10^4s = 235 J/s = 235 Watts.
B. Work = F*d = Mg*d = 1850*9.8 * 1.2 =
21,756 J.
t = 21,756J./(235J/s) = 92.6 s.
What is the average useful power output of a person who does 5.50×106 J of useful work in 6.50 h?
Working at this rate, how long will it take this person to lift 1850 kg of bricks 1.20 m to a platform? (Work done to lift his body can be omitted because it is not considered useful output here.)
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