Question
A 62 kg hiker climbs to the top of a 3700 m-high mountain. The climb is made in 5.0 h starting at an elevation of 2600 m. Calculate the average power output in watts. Calculate the average power output in horsepower.
Answers
First you need to calculate the PE needed to make the climb.
U=mgh U=(62*(2600-3700)*9.8)
This value is energy or work denoted as a Joule. A Watt= Joule/Seconds
So simply take your joules and divide it by the time the trip took. Convert your 5hr to seconds so...
W=(62*(2600-3700)*9.8)/(5*3600)
easy way to find HP is 1W=0.00134102209HP or
HP=(62*(2600-3700)*9.8)/(5*3600)*0.00134102209
U=mgh U=(62*(2600-3700)*9.8)
This value is energy or work denoted as a Joule. A Watt= Joule/Seconds
So simply take your joules and divide it by the time the trip took. Convert your 5hr to seconds so...
W=(62*(2600-3700)*9.8)/(5*3600)
easy way to find HP is 1W=0.00134102209HP or
HP=(62*(2600-3700)*9.8)/(5*3600)*0.00134102209
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