Asked by Kayla
In moving a 35kg desk from one side of a room to another, a man finds that a horizontal force of 275N is necessary to set the desk in motion, and a force of 195N is necessary to keep it in motion at a constant speed. What are the coefficients of both static friction and kinetic Friction between the desk and the floor?
Show all your calculations.
Show all your calculations.
Answers
Answered by
Henry
M*g = 35 * 9.8 = 343 N. = Wt. of the desk = Normal force(Fn).
A. Fap-Fs = M*a.
275-Fs = 35*0
275-Fs = 0
Fs = 275 N. = Force of static friction.
us = Fs/Fn = 275/343 =[
B. Fap-Fk = M*a.
195-Fk = 35*0
Fk = 195 N. = Force of kinetic friction.
uk = Fk/Fn = 195/343
A. Fap-Fs = M*a.
275-Fs = 35*0
275-Fs = 0
Fs = 275 N. = Force of static friction.
us = Fs/Fn = 275/343 =[
B. Fap-Fk = M*a.
195-Fk = 35*0
Fk = 195 N. = Force of kinetic friction.
uk = Fk/Fn = 195/343