Hello this is my first experiment I've ever done before and it was fun but I gotta figure out what NaCl produced and what it yielded in percentage. Can someone double check my work.

Na2CO3+2HCl=2NaCl+H2O+CO2

Mass of empty crucible & cover: 33.076g
Mass of sodium carbonate used to start experiment: 0.575g Na2CO3
Mass of crucible, cover & sodium chloride after experiment: 33.653g NaCl

My answers:

Sodium Chloride produced: (0.575gNa2CO3/106gNa2CO3) x (2mole NaCl/1moleNaCO3) x 58gNaCl mole = 66.7/106g = 0.629g NACl
--->I used 3 sig figs because the starting amount of sodium chloride was 3 sig figs.<---

Actual mass of NaCl produced: 33.653-33.076= 0.577g NaCl

Percentage yielded: 0.577gNaCl/0.629NaCl= .917 x 100= 92%

Thanks for checking my work.