Asked by Johnny
Mg + 2HCl ----> MgCl2 + H2
What volume of hydrogen at STP is produced from the reaction of 50.0g of Mg and the equivalent if 75g of HCl?
1. What is the limiting reagent?
2. What is the volume of hydrogen produced?
3. How much is in excess?
What volume of hydrogen at STP is produced from the reaction of 50.0g of Mg and the equivalent if 75g of HCl?
1. What is the limiting reagent?
2. What is the volume of hydrogen produced?
3. How much is in excess?
Answers
Answered by
Johnny
But what does "volume=22.4*1.04 dm^3" mean???
I'm new to chemistry so don't know the lingo that well. Would it be 23.3 excess?
I'm new to chemistry so don't know the lingo that well. Would it be 23.3 excess?
Answered by
bobpursley
molesMg=50/26=1.92
molesHCl=75/36=2.08
clearly you do not have enougth HCl to consume all the Mg.
Limiting Reagent: HCl
volume H2: moles H2=1/2 moles HCL=1.04
volume=22.4*1.04 dm^3 that is the volume in decimeters^3 (some still call that a liter)
excess excess. I assume that means excess Mg, as it was not all used up.
You used: moles HCl=2.08, or then moles Mg 1.04*26 or 27 grams, so you have 50-27 g of Mg left over, or in excess then of 23 grams.
molesHCl=75/36=2.08
clearly you do not have enougth HCl to consume all the Mg.
Limiting Reagent: HCl
volume H2: moles H2=1/2 moles HCL=1.04
volume=22.4*1.04 dm^3 that is the volume in decimeters^3 (some still call that a liter)
excess excess. I assume that means excess Mg, as it was not all used up.
You used: moles HCl=2.08, or then moles Mg 1.04*26 or 27 grams, so you have 50-27 g of Mg left over, or in excess then of 23 grams.
Answered by
Mike
Awesome thank you I wanted to make sure I understand you meant. So it looks like we got the same answer of excess= 23g Mg
Thanks!
Thanks!