Asked by Eyasu Abraham

A ball of mass 4 Kg falls to the floor; it lands with a speed of 6 m/s.it bounces off with same speed.show that its momentum has changed by 48 kg m/s?
Answered by Damon
initial momentum = -4 * 6
final momentum = +4*6
change in momentum = +24 - (-24 ) = +48
Answered by Aragu Girma
A ball of Mass 4kg falls to floor; it lands with a speed of 6m/s. It bounces off with the same speed . show that momentum has changed by 48kgm/s
Answered by Belaynesh
Physics
Answered by yohans
A ball of Mass 4kg falls to floor; it lands with a speed of 6m/s. It bounces off with the same speed . show that momentum has changed by 48kgm/s

Answered by Seada
Parent
Answered by Seada
Student
Answered by Nejash
Good
Answered by Qalli
Smart
Answered by hewan
initial momentum= m×v final momentum= -m×v
=4×6 =-4×6
=24kgm/s =-24kgm/s

change in momentum
=initial momentum - final momentum
= 24-(-24)=48kgm/s
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Answer
The initial momentum is negative 4 times 6
And then the final momentum is positive 4 times 6
So the change in momentum will be
+24-(-24) which is equal to 48kgm|s
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