Asked by Gifty
Prove this identity
1. csc^2(pi/2-x)=1+sin^2xcsc^2(pi/2-x)
2. tan(pi/4+x)+tan(pi/4-x)=2sec2x
1. csc^2(pi/2-x)=1+sin^2xcsc^2(pi/2-x)
2. tan(pi/4+x)+tan(pi/4-x)=2sec2x
Answers
Answered by
Reiny
I will do the first one.
LS = 1/ sin^2(pi/2 - x)
= 1/(sin(pi/2)cosx = cos(pi/2)sinx)^2
= 1/(cosx)^2
RS = 1 + sin^2x/sin^2(pi/2 - x)
= 1 + sin^2x/cos^2x --- we did that part in LS
= (cos^2 + sin^2x)/cos^2x --- common denominator etc
= 1/cos^2x
= LS
for the second I would change the tan to sin/cos and use the expansion formulas
give it a try.
LS = 1/ sin^2(pi/2 - x)
= 1/(sin(pi/2)cosx = cos(pi/2)sinx)^2
= 1/(cosx)^2
RS = 1 + sin^2x/sin^2(pi/2 - x)
= 1 + sin^2x/cos^2x --- we did that part in LS
= (cos^2 + sin^2x)/cos^2x --- common denominator etc
= 1/cos^2x
= LS
for the second I would change the tan to sin/cos and use the expansion formulas
give it a try.
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