Asked by Anonymous
One of Anne’s most important duties at the clinic is to prepare solutions with the correct amount of anesthetic for animals undergoing surgery. For today’s surgery, she needs 250 milliliters of a 20% solution, but only has a 10% solution and a 60% solution available.
How many milliliters of the 10% solution must Anne mix with the 60% solution to obtain the required solution?
How many milliliters of the 10% solution must Anne mix with the 60% solution to obtain the required solution?
Answers
Answered by
Reiny
amount of the 10% solution ---- x ml
amount of the 60% solution ---- 250-x ml
.1x + .6(250-x) = .2(250)
times 10
x + 6(250-x) = 2(250)
x + 1500 - 6x = 500
-5x = -1000
x = 200
so 200 ml of the 10% stuff, and 50 ml of the 60% stuff
amount of the 60% solution ---- 250-x ml
.1x + .6(250-x) = .2(250)
times 10
x + 6(250-x) = 2(250)
x + 1500 - 6x = 500
-5x = -1000
x = 200
so 200 ml of the 10% stuff, and 50 ml of the 60% stuff
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