Three zeroes of a fifth degree polynomial function are 1/3, 4 - 6i, and -2 + 11i. Determine the remaining zeroes of the function.

4 + 6i, -2 - 11i
-1/3, 4 + 6i, 2 + 11i
-4 + 6i, 2 - 11i
3, 4 + 6i, -2 - 11i

Can I have some guidance for this please? I am unsure how to solve this. Thanks

4 answers

complex roots (containing "i") occur in conjugate pairs
... if a+bi is a root, then a-bi is also
Okay, so would it be the second option?
I believe I am incorrect since it's a fifth degree function and I do not think -1/3 is pliable. I think it's the first option.
A. 4+6i,-2-11i :)
Similar Questions
    1. answers icon 2 answers
    1. answers icon 1 answer
  1. true/false1. a cubic polynomial has at least one zero.............. 2. a quadratic polynomial an have at most two
    1. answers icon 4 answers
  2. Without graphing the function f(x)=(2x+1)(x-4)^2 determine:a) the degree of the function b) the type of polynomial function c)
    1. answers icon 4 answers
more similar questions