Asked by Max

Three zeroes of a fifth degree polynomial function are 1/3, 4 - 6i, and -2 + 11i. Determine the remaining zeroes of the function.

4 + 6i, -2 - 11i
-1/3, 4 + 6i, 2 + 11i
-4 + 6i, 2 - 11i
3, 4 + 6i, -2 - 11i

Can I have some guidance for this please? I am unsure how to solve this. Thanks
Answered by Scott
complex roots (containing "i") occur in conjugate pairs
... if a+bi is a root, then a-bi is also
Answered by Max
Okay, so would it be the second option?
Answered by Max
I believe I am incorrect since it's a fifth degree function and I do not think -1/3 is pliable. I think it's the first option.
Answered by koyo
A. 4+6i,-2-11i :)
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