Is this the correct structure for cis-3-octene?

Question

CH3-CH2 CH2-CH2-CH2-CH3 
\ / 
C=C 
/ \ 
H H

I can't tell what you have since we can't do spacing on the computer. But I think I can draw it like this: 
CH3-CH2-C=C-CH2CH2CH2CH3 
Now stick a H atom to the #3 and one to the #4 C atoms, both on the same side, to make it cis.

Ok I think I have it correct but I have one more question, is there supposed to be a bond between each atom on the right side as well as the left. I see you did not put one and I did. Am I wrong? I missed this lecture in class so I am a little lost.

Thanks

No, you are not wrong. Sometimes we write it as CH3CH2CH2CH2 etc and sometimes CH3-CH2-CH2-CH2 etc. 
The second way, some purists think, says that H is bonded to C without a C-C bond there but we all know what it means. If the computer would let us put in spaces, then we could write the skeleton structure as 
C-C-C=C-C-C-C-C and have H atoms hanging on to the appropriate C atom but the difficulty in the spacing problem we have prevents that.

the structure of 1,2,2-trimethylcyclopentane