Asked by Emily
I cannot figure out what the answer to this problem is. Can somebody help plz? any help is greatly appreciated!
Tony swims 100 m downstream in 175 seconds. It takes him 400 seconds to swim back upstream.
5. Find Tony's rate with the current. I got r+c=175, where r=Tony's rate and c=rate of current.
6. Find Tony's rate against the current. I got r-c=400.
7. Find Tony's rate with no current.
8. Find the rate of the current.
9. What are the total distance and total time?
10. Find Tony's average speed.
Ok, I tried the addition method thing where you add r+c=175 to r-c=400 and you get 2r=575 which equals r=287.5, but it isn't possible. Can somebody help? I might be able to figure out problems 8.-10., but I don't get problem 7. Oh, and one more question...what would be the units for his average speed? Would it be meters/seconds?
Thank you very very very much!
try doing what tonyt did and count the time it takes
uh... what do you mean by that?
make a chart and it becomes very easy
-------------Dist------Rate-----Time
upstream---400(r+c)m---r+c m/s---400 sec
downstream-175(r-c)m---r-c m/s---175 sec
but we know the distance is 100 m, so...
400(r+c)=100
175(r-c)=100
r+c=1/4 I divided by 100
r-c= 4/7 I divided by 175
add these two
2r=23/28
r=23/56 m/s or .411 m/s
sub back to get c=.161 m/s
Tony swims 100 m downstream in 175 seconds. It takes him 400 seconds to swim back upstream.
5. Find Tony's rate with the current. I got r+c=175, where r=Tony's rate and c=rate of current.
6. Find Tony's rate against the current. I got r-c=400.
7. Find Tony's rate with no current.
8. Find the rate of the current.
9. What are the total distance and total time?
10. Find Tony's average speed.
Ok, I tried the addition method thing where you add r+c=175 to r-c=400 and you get 2r=575 which equals r=287.5, but it isn't possible. Can somebody help? I might be able to figure out problems 8.-10., but I don't get problem 7. Oh, and one more question...what would be the units for his average speed? Would it be meters/seconds?
Thank you very very very much!
try doing what tonyt did and count the time it takes
uh... what do you mean by that?
make a chart and it becomes very easy
-------------Dist------Rate-----Time
upstream---400(r+c)m---r+c m/s---400 sec
downstream-175(r-c)m---r-c m/s---175 sec
but we know the distance is 100 m, so...
400(r+c)=100
175(r-c)=100
r+c=1/4 I divided by 100
r-c= 4/7 I divided by 175
add these two
2r=23/28
r=23/56 m/s or .411 m/s
sub back to get c=.161 m/s
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