No need now thanks everyone.
*In case you need the answer,it is 40.
*In case you need the answer,it is 40.
My age = 3x years old.
Five yrs. ago:
My son's age: x-5.
My age: 3x-5.
3x-5 = 4(x-5).
3x-5 = 4x-20
X = 15 = My son's age now.
my son
Let's say your current age is represented by "x" and your son's current age is represented by "y". According to the information given, we know that:
1) Your son is currently 1/3 of your age: y = (1/3)x
2) Five years ago, your son was 1/4 of your age: y - 5 = (1/4)(x - 5)
To solve this system of equations, we can use substitution or elimination.
Using substitution, we substitute the value of y from equation 1) into equation 2):
(1/3)x - 5 = (1/4)(x - 5)
Now, we can solve for x:
Multiply both sides of the equation by 12 to eliminate the fractions:
12[(1/3)x - 5] = 12[(1/4)(x - 5)]
4x - 60 = 3(x - 5)
4x - 60 = 3x - 15
Subtract 3x from both sides:
4x - 3x - 60 = -15
x - 60 = -15
Add 60 to both sides:
x = -15 + 60
x = 45
So, your current age is 45.
Now, substituting this value back into equation 1) to find your son's age:
y = (1/3)(45)
y = 15
Therefore, your son is currently 15 years old.