Asked by Muff
A ball is dropped from the height of 20m. It bounces 60% of its previous height each bounce. The total distance travelled is made of the upward and downward bounces. What is the total vertical distance the ball has travelled after the sixth bounce?
Answers
Answered by
Steve
A geometric series with a=40 (for a round trip) and r = 0.6
S6 = 40(1-.6^6)/(1-.6) = 95.33
Now subtract 20 from that, since the 1st "bounce" started from the top.
S6 = 40(1-.6^6)/(1-.6) = 95.33
Now subtract 20 from that, since the 1st "bounce" started from the top.
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