Ask a New Question

Asked by suraj

A stone is dropped from a height of 10 m on an unknown planet having g = 20 m/s2.
Calculate the speed of the stone when it hits the surface of the planet. Also calculate the
time it takes to fall through this height
11 years ago

Answers

Answered by Henry
V^2 = Vo^2 + 2g*h = 0 + 40*10 = 400
V = 20 m/s.

0.5g*t^2 = 10 m.
10*t^2 = 10
t^2 = 1
t = 1 s.

Or
V = Vo + g*t = 20
V = 0 + 20t = 20
t = 1 s.
11 years ago

Related Questions

1.A ball is dropped from a height of 2.0, to a floor. After each bounce, the ball rises to 63% of it... A marble is dropped from a height of 10 m. A 2nd marble is rolled off a 10 m table at 5 m/s. A 3rd m... A ball is dropped from a height of 5 ft. Assuming that on each bounce the ball rebounds to one-thi... a ball is dropped from the height. if it takes 0.2 sec. to cross the last 6 m before hitting the gro... A particle is dropped from height 100m and A ball is dropped from the height of 20m. It bounces 60% of its previous height each bounce. The tot... When a ball dropped from a height it's speed continuously increased Give reason A tennis is dropped from a height of 256m . Each time the ball bounces , it rises 3/4 of the previou... Object To Be Dropped Drop Height (meters) 10-gram ball 5-gram ball 18-gram ball 5 8 10 A stu...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use