Asked by Delila

of all the houses in a certain neighborhood,80 % have garages.Of those houses with garages 60% have two car garages.If there are 56 houses with garages that are not two car garages,how many houses are there in the neighborhood.
How do I do this using percent change ?

Answers

Answered by Steve
there is no change involved. If there are x houses in total, then

.80x have garages
60% of those have two-car garages, so 40% have garages that are not two-car.

.80x * .40 = 56
x = 175
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