Asked by Delila
of all the houses in a certain neighborhood,80 % have garages.Of those houses with garages 60% have two car garages.If there are 56 houses with garages that are not two car garages,how many houses are there in the neighborhood.
How do I do this using percent change ?
How do I do this using percent change ?
Answers
Answered by
Steve
there is no change involved. If there are x houses in total, then
.80x have garages
60% of those have two-car garages, so 40% have garages that are not two-car.
.80x * .40 = 56
x = 175
.80x have garages
60% of those have two-car garages, so 40% have garages that are not two-car.
.80x * .40 = 56
x = 175
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.