Question

of all the houses in a certain neighborhood,80 % have garages.Of those houses with garages 60% have two car garages.If there are 56 houses with garages that are not two car garages,how many houses are there in the neighborhood.
How do I do this using percent change ?

Answer 1

there is no change involved. If there are x houses in total, then

.80x have garages
60% of those have two-car garages, so 40% have garages that are not two-car.

.80x * .40 = 56
x = 175