Asked by Sarah
Describe the following transformations on y=x^2:
y=-4(2x+10)^2 -7
y=-4(2x+10)^2 -7
Answers
Answered by
Scott
the -4 and the x-coefficient cause the parabola to open downward and "stretch out" in the y direction
the 10 and the -7 move the vertex away from the origin
the 10 and the -7 move the vertex away from the origin
Answered by
Reiny
Make a preliminary sketch of y = x^2
y=-4(2x+10)^2 -7
= -4(2^2)(x+5)^2 - 7
= -16(x+5)^2 - 7
The vertex of y = x^2, which was (0,0) is now (-5,-7), the direction is now downwards, the parabola is stretched by a factor of 16, which makes it much more "pointed"
y=-4(2x+10)^2 -7
= -4(2^2)(x+5)^2 - 7
= -16(x+5)^2 - 7
The vertex of y = x^2, which was (0,0) is now (-5,-7), the direction is now downwards, the parabola is stretched by a factor of 16, which makes it much more "pointed"
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