Asked by john wiliams

Bob has a helicopter and from the launch pad he flies the following path: First he travels from the launch pad a distance of 24 kilometers at heading of 60 degrees East of South. Then he flies 48 kilometers heading 75 degrees West of North. After this he flies 35 kilometers heading 77 West of North. Now he is ready to return directly to the launch pad. What is the displacement vector that he needs to take to return directly to the launch pad from his present location (for the heading give the number degrees north of east - your answer may be greater than 90 degrees)?
Answered by Steve
24@S60°E = (24sin60°,-24cos60°)
48@n75°W = (-48sin75°,48cos75°)

Now just add them up, and convert back to compass heading.
Answered by john wiliams
what about 35 km @ 77 degrees ? do i just do 35@n77°W = ( -35sin77°, 35cos77° )? or did you already add it into the other north of west?
Answered by john wiliams
and also, which ones should i be adding together? the x's together and y's together?
Answered by Henry
See previous post: Sun, 10-8-17, 10:47PM.
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