Asked by Kane
How many grams of O_2(g) are needed to react completely with 3.95 g of H_2(g) according to the following balanced chemical equation: 2H_2(g) + O_2(g)--> 2H_2_O(g)
Molarity (M) is the number of moles of a solute per 1 L of solution--> M= (mol solute)/(L solution). How many moles of permanganate are in 8.23 L of a 3.78 M solution?
Molarity (M) is the number of moles of a solute per 1 L of solution--> M= (mol solute)/(L solution). How many moles of permanganate are in 8.23 L of a 3.78 M solution?
Answers
Answered by
bobpursley
steps:
how many moles of H2 is 3.95g?
you need for each mole of H2, half as many moles of O2?
how many grams is that?
moles=molarity*liters
how many moles of H2 is 3.95g?
you need for each mole of H2, half as many moles of O2?
how many grams is that?
moles=molarity*liters
Answered by
Kane
@bobpursley
Molarity= 3.78/8.23= 0.459
0.459=molarity
0.459 x 8.23= 3.78moles
Molarity= 3.78/8.23= 0.459
0.459=molarity
0.459 x 8.23= 3.78moles
Answered by
Kane
I got 31.6 g of O2 for #1 is that correct?
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