Asked by Anonymous
How many grams of Cu would be created if 9.1g of Al was reacted via the following reaction?
2Al + 3CuCl2 → 3Cu + 2AlCl3
2Al + 3CuCl2 → 3Cu + 2AlCl3
Answers
Answered by
Anonymous
3 mols of Cu for every 2 mols of Al
mols of Al = 9.1 g * ( 1 mol / 27 g)
mols of Cu = (3/2) * ( 9.1/27)
grams of Cu = mols of Cu * ( 63.5 grams/1mol)
mols of Al = 9.1 g * ( 1 mol / 27 g)
mols of Cu = (3/2) * ( 9.1/27)
grams of Cu = mols of Cu * ( 63.5 grams/1mol)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.