Question
Roger tosses a ball straight upward at a velocity of +32m/s, calculate the maximum height of the ball and the time to get to the maximum height.
Answers
Henry
V = Vo + g*Tr = 0.
32 - 9.8Tr = 0
Tr = 3.27 s. = Rise time or time to reach max ht.
h = Vo*Tr + 0.5g*Tr^2.
Vo = 32 m/s, Tr = 3.27 s., g = -9.8 m/s^2, h = ?.
32 - 9.8Tr = 0
Tr = 3.27 s. = Rise time or time to reach max ht.
h = Vo*Tr + 0.5g*Tr^2.
Vo = 32 m/s, Tr = 3.27 s., g = -9.8 m/s^2, h = ?.