Asked by Anthony
An acrobat hangs from a trapeze with the tension in both ropes is 315 Newtons.What is the mass of the acrobat?
Answers
Answered by
bobpursley
Hmmmm.
on the trapeze, if it is still, hanging downward, mass*9.8=2*315
solve for msss
one the second, each side is holding half the weight.
(1/2 * 87.9*9.8)/tension= sin10.1deg
solve for tension.
on the trapeze, if it is still, hanging downward, mass*9.8=2*315
solve for msss
one the second, each side is holding half the weight.
(1/2 * 87.9*9.8)/tension= sin10.1deg
solve for tension.
Answered by
Henry
M*g = 87.9 * 9.8 = 861.4 N. = Wt. of acrobat.
All angles are referenced to +x-axis.
T1*sin(180-10.1) + T2*sin(10.1) = 861.4.
0.1754T1 + 0.1754T2 = 861.4
T2 = T1
0.1754T1 + 0.1754T1 = 861.4
0.3507T1 = 861.4
T1 = 2456 N. = T2.
All angles are referenced to +x-axis.
T1*sin(180-10.1) + T2*sin(10.1) = 861.4.
0.1754T1 + 0.1754T2 = 861.4
T2 = T1
0.1754T1 + 0.1754T1 = 861.4
0.3507T1 = 861.4
T1 = 2456 N. = T2.
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