Asked by John1234
If a trapeze artist rotates twice each second while sailing through the air, and contracts to reduce her rotational inertia to one-third, how many rotations per second will result?
Answers
Answered by
Elena
According to the Law of conservation of angular momentum
L1= L2,
I1•ω1=I2•ω2.
ω1=2πn1
ω2=2πn2
I2=I1/3.
Then n2=(I1/I2)n1=3•2=6 s-1
L1= L2,
I1•ω1=I2•ω2.
ω1=2πn1
ω2=2πn2
I2=I1/3.
Then n2=(I1/I2)n1=3•2=6 s-1
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