Asked by samiksha
A bullet m9ving at a speed of 10m/s strikes a wooden plank . The bullet penetrates the plank 2cm deep and remains embedded in it . The acceleration of the bullet is?
Answers
Answered by
Damon
d = .02 meters
average speed = 5 m/s
time = .02 meters/ 5 m/s = .004 seconds
a = change in speed / time
= -10/.004 = -2500 m/s^2
or
d = 10 t + (1/2) a t^2
.02 = .04 + (1/2)a 1.6 *10^-5
.02 = .04 + .8*10^-5 a
.8 * 10^-5 a = -.02
a = -2500 again
average speed = 5 m/s
time = .02 meters/ 5 m/s = .004 seconds
a = change in speed / time
= -10/.004 = -2500 m/s^2
or
d = 10 t + (1/2) a t^2
.02 = .04 + (1/2)a 1.6 *10^-5
.02 = .04 + .8*10^-5 a
.8 * 10^-5 a = -.02
a = -2500 again
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