Asked by Sharpshooter
For #1-4, write an equation of the line that passes through each pair of points. Show all of your work to receive full credits.
1.) (9, -2) and (4, 3)
Answer: 9 = -1x + -2
2.) (3, 5) and (2, -2)
Answer: 3 = 7x + 5
3.) (4, 3) and (2, 0)
Answer: 4 = 2/3x + 3
4.) (5, 2) and (15, -10)
Answer: 15 = -6/5x + -10
Could someone please check my work? Thanks so much :)
1.) (9, -2) and (4, 3)
Answer: 9 = -1x + -2
2.) (3, 5) and (2, -2)
Answer: 3 = 7x + 5
3.) (4, 3) and (2, 0)
Answer: 4 = 2/3x + 3
4.) (5, 2) and (15, -10)
Answer: 15 = -6/5x + -10
Could someone please check my work? Thanks so much :)
Answers
Answered by
Reiny
none are correct
A typical equation of a straight line, other than vertical or horizontal lines, need an x and a y variable.
I will do one of them , say #4, you do the others
slope of line = (-10-2)/(15-5) = -12/10 = -6/5
using the point (5,2),
y - 2 = (-6/5)(x-5)
multiply both sides by 5
5y - 10 = -6x + 30
6x + 5y = 40
or in the form y = mx + b
y = (-6/5)x + b
sub in the point (5,2)
2 = (-6/5)(5) + b
2 = -6 + b
b = 8
y = (-6/5)x + 8
use whichever method you learned.
A typical equation of a straight line, other than vertical or horizontal lines, need an x and a y variable.
I will do one of them , say #4, you do the others
slope of line = (-10-2)/(15-5) = -12/10 = -6/5
using the point (5,2),
y - 2 = (-6/5)(x-5)
multiply both sides by 5
5y - 10 = -6x + 30
6x + 5y = 40
or in the form y = mx + b
y = (-6/5)x + b
sub in the point (5,2)
2 = (-6/5)(5) + b
2 = -6 + b
b = 8
y = (-6/5)x + 8
use whichever method you learned.
Answered by
Sharpshooter
Thanks so much! My teacher explained it really terribly and I didn't realize until I turned in the homework assignment I missed entire steps :P
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