(total acc)^2 = tangential^2 + centripetal^2
centripetal = V1^2 / r
1/8 2 π r = 1/2 (tngtl) t^2 + V1 t
V2 = V1 (tngtl) t
At some instant, a particle traveling in a horizontal circular path of radius 3.30 m has a total acceleration with a magnitude of 18.0 m/s2 and a constant tangential acceleration of 12.0 m/s2. Determine the speed of the particle at this instant and (1/8) revolution later.
initial speed: _____m/s
final speed: ______m/s
1 answer