Asked by John
1. Start from rest with constant acceleration of 2.11 m/s2 for 20.0 s.
2. Maintain a constant velocity for the next 2.75 min.
3. Apply a constant negative acceleration of −8.44 m/s2 for 5.00 s.
(a) What was the total displacement for the trip?
Please explain with steps and an answer! Thank you!
2. Maintain a constant velocity for the next 2.75 min.
3. Apply a constant negative acceleration of −8.44 m/s2 for 5.00 s.
(a) What was the total displacement for the trip?
Please explain with steps and an answer! Thank you!
Answers
Answered by
bobpursley
draw the velocity (graph) vs time.
The area under the graph is distance, you can break the areas up into two triangles, and one rectangle, and count the squares (or use formulas for those ), add.
displacement=velocity*time
The area under the graph is distance, you can break the areas up into two triangles, and one rectangle, and count the squares (or use formulas for those ), add.
displacement=velocity*time
Answered by
Damon
Step 1
v = 0 + 2.11 * 20 = 42.2 m/s
x = 0+0(20)+(1/2)*2.11*20^2=422 meters
so we are at 42.2 m/s and 422 m
Step 2
2.75*60 = 165 s
v = 42.2
x = 422 * 42.2 (165) + (1/2)*0*165^2
= 7385 meters
step 3
x = 7385 + 42.2(5) -(1/2)(8.44)(25)
= 7385 + 211 - 105.5
= 7491 meters
v = 0 + 2.11 * 20 = 42.2 m/s
x = 0+0(20)+(1/2)*2.11*20^2=422 meters
so we are at 42.2 m/s and 422 m
Step 2
2.75*60 = 165 s
v = 42.2
x = 422 * 42.2 (165) + (1/2)*0*165^2
= 7385 meters
step 3
x = 7385 + 42.2(5) -(1/2)(8.44)(25)
= 7385 + 211 - 105.5
= 7491 meters
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