Question

Two cars start from rest at a red stop light. When the light turns green, both cars accelerate forward. The blue car accelerates uniformly at a rate of 4.8 m/s2 for 4.5 seconds. It then continues at a constant speed for 9.9 seconds, before applying the brakes such that the car’s speed decreases uniformly coming to rest 309 meters from where it started. The yellow car accelerates uniformly for the entire distance, finally catching the blue car just as the blue car comes to a stop. How fast is the blue car going 2.3 seconds after it starts?

Answer 1

You just use the equation vf=vi+at. Your initial velocity would be zero since it's starting from rest, your acceleration in this case would be 4.8 m/s^2, and your time would be 2.3 seconds. Your answer will be 11.04 m/s.

Answer 2

11.04