59.0 mL of a 1.60 M solution is diluted to a total volume of 268 mL. A 134-mL portion of that solution is diluted by adding 173 mL of water. What is the final concentration? Assume the volumes are additive?

Answer 1

59.0 mL of a 1.60 M solution is diluted to a total volume of 268 mL

The volume is increased by a factor of 268/59. So, the concentration is reduced by that factor.

59/268 * 1.60 = 0.3522M

Now the volume is increased by a factor of 307/134, so the concentration is reduced by that factor:

134/307 * .3522 = 0.154M