#1. 2,3,1,3 but check it to make sure.
The others. You need to learn to do these yourself. Tell us what you don't understand about the process and we can help you through it.
1.) __BF3 + __Li2SO3 --> __B2(SO3)3 + __LiF
2.) __CaCO3 + __H3PO4 --> __Ca3(PO4)2 + __H2CO3
3.) __B2Br6 + __HNO3 --> __B(NO3)3 + __HBr
The others. You need to learn to do these yourself. Tell us what you don't understand about the process and we can help you through it.
if it does wouldn't that mean the first would be B2F6 and the last would be Li3F3, so the F would be unbalanced?
i don't get that part...
I made a typo. I typed 2,3,1,3 and I SHOULD have typed 2,3,1 6.
In answer to your question, no. The first rule of balancing equations is that you may change ONLY the coefficients. You may NOT change the subscripts. Therefore, placing a 2 as a coefficient for BF3 (2BF3) means you multiply the B and the F by 2 which gives you 2 B atoms and 6 F atoms. And that balances with the B2(SO3(3 (2 B atoms there) and the 6LiF (6 F atoms there).
would the next one #2 be 3, 2, 1, 3
idk haha
You ALWAYS know if the equation is balanced BECAUSE you ALWAYS check it after finishing. That way you will know if you made an error. Let's check this one.
I'll put in your numbers.
B2Br6 + 6HNO3 ==> 2B(NO3)3 + 6HBr
I see 2 B on the left and 2 on the right.
I see 6 Br on the left and 6 on the right.
I see 6H on the left and 6 on the right.
I see 6 NO3^- on the left and 6 on the right.
Looks to me as if you scored again! Good work!
1.) __BF3 + __Li2SO3 --> __B2(SO3)3 + __LiF
To balance this equation, start by counting the number of atoms of each element on both sides of the equation:
On the left side:
B: 1
F: 3
Li: 2
S: 1
O: 3
On the right side:
B: 2
F: 1
S: 3
O: 9
Li: 1
Since the numbers of atoms on each side are not balanced, you need to adjust the coefficients in front of each compound.
By trying different coefficients, you can balance the equation as follows:
2BF3 + 3Li2SO3 --> B2(SO3)3 + 6LiF
Now, recheck the number of atoms of each element:
On the left side:
B: 2
F: 6
Li: 6
S: 3
O: 9
On the right side:
B: 2
F: 6
S: 3
O: 9
Li: 6
The equation is now balanced.
2.) __CaCO3 + __H3PO4 --> __Ca3(PO4)2 + __H2CO3
Start by counting the number of atoms of each element on both sides of the equation:
On the left side:
Ca: 1
C: 1
O: 3
H: 3
P: 1
On the right side:
Ca: 3
P: 2
O: 8
H: 2
C: 1
The numbers of atoms on each side are not balanced.
By adjusting the coefficients, the equation can be balanced as follows:
3CaCO3 + 2H3PO4 --> Ca3(PO4)2 + 3H2CO3
After balancing, recheck the number of atoms of each element:
On the left side:
Ca: 3
C: 3
O: 9
H: 6
P: 6
On the right side:
Ca: 3
P: 6
O: 9
H: 6
C: 3
The equation is now balanced.
3.) __B2Br6 + __HNO3 --> __B(NO3)3 + __HBr
Start by counting the number of atoms of each element on both sides of the equation:
On the left side:
B: 2
Br: 6
H: 1
N: 1
O: 3
On the right side:
B: 1
N: 3
O: 9
H: 1
Br: 1
Since the numbers of atoms on each side are not balanced, you need to adjust the coefficients in front of each compound.
By trying different coefficients, you can balance the equation as follows:
B2Br6 + 6HNO3 --> 3B(NO3)3 + 6HBr
Now, recheck the number of atoms of each element:
On the left side:
B: 2
Br: 6
H: 6
N: 6
O: 18
On the right side:
B: 6
N: 18
O: 54
H: 6
Br: 6
The equation is now balanced.