Asked by john
FROM THE SKYDOME IN SM NORTH WHICH DIRECTLY ACROSS THE STREET, THE ANGLE OF ELEVATION OF TRINOMA IS 57°20' AND THE ANGLE OF DEPRESSION OF THE BASE IS 18°10'. IF THE BUILDING ARE 105 METERS APART, WHAT IS THE HEIGHT OF THE BUILDING?
Answers
Answered by
Henry
Tan18.16 = h1/105.
h1 = 105*Tan18.16 = 34.44 m. = Height of Sky dome.
h = h1 + h2.
h = 34.44 + 105*Tan57.33 = 198.2 m. = Ht. of Trinoma.
h1 = 105*Tan18.16 = 34.44 m. = Height of Sky dome.
h = h1 + h2.
h = 34.44 + 105*Tan57.33 = 198.2 m. = Ht. of Trinoma.
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