Asked by Himani
4m=cotA(1+SinA), 4n=cotA(1-SinA)
Proved that
(m2-n2)=mn
Proved that
(m2-n2)=mn
Answers
Answered by
Steve
There must be a typo. Plug in A = pi/4 and you have
4m = (1 + 1/√2), so m = (2+√2)/8
4n = (1 - 1/√2), so n = (2-√2)/8
m2-n^2 = √2/8
mn = 1/32
4m = (1 + 1/√2), so m = (2+√2)/8
4n = (1 - 1/√2), so n = (2-√2)/8
m2-n^2 = √2/8
mn = 1/32
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